The common denominator for both fractions is abc^3.
(a-1)/(abc^3) + (3-b)/(abc^3) = (a-1 + 3-b)/(abc^3)
= (a+2-b)/(abc^3)
Therefore, the sum is (a+2-b)/(abc^3)
what is the sum (a-1)/(abc^(3))+(3-b)/(abc^(3))
3 answers
The answers are,
A: a - b - 3/abc^3
B: a - b - 3/abc^3
C: a - 4 + b/abc^3
D: a - b + 2/abc^3
A: a - b - 3/abc^3
B: a - b - 3/abc^3
C: a - 4 + b/abc^3
D: a - b + 2/abc^3
Let's simplify the expression further:
(a-1)/(abc^3) + (3-b)/(abc^3)
= (a + 3 - 1 - b) / (abc^3)
= (a + 2 - b) / (abc^3)
So the correct answer is A: a + 2 - b / (abc^3)
(a-1)/(abc^3) + (3-b)/(abc^3)
= (a + 3 - 1 - b) / (abc^3)
= (a + 2 - b) / (abc^3)
So the correct answer is A: a + 2 - b / (abc^3)