well, didn't you use your distance formula?
√(-4-(-2))^2+(-9-(-7))^2) = √((-2)^2+(-2)^2) = √(4+4) = √8 = 2√2
What is the straight-line distance between (-2, -7) and (-4, -9) on a coordinate graph?
A. 2 sqrt2
B. 2 sqrt3
C. 2
D. 3
I think that it might be A or C but I'm unsure.
3 answers
draw lines through the points in the x and y directions
find the right triangle whose hypotenuse is the distance you want
... the lengths of the sides are the distances between the two points in the x ... and y directions
you can also find the x and y distances by subtracting the corresponding coordinates of the points
(distance)^2 = (x-distance)^2 + (y-distance)^2
find the right triangle whose hypotenuse is the distance you want
... the lengths of the sides are the distances between the two points in the x ... and y directions
you can also find the x and y distances by subtracting the corresponding coordinates of the points
(distance)^2 = (x-distance)^2 + (y-distance)^2
Aah, okay. Again, I was unsure of the process as this was a review question on a lesson I don't remember. Thank you.