What is the standard form of this parabola:

Question

-2x^2+16x+24y-224=0

Please Help, parabolas are evil.

Answer 1

Divide both sides by -2 and complete the square for the x^2 binomial.

x^2 -8x -12y +112 = 0
x^2 -8x +16 -12y +96 = 0
(x -4)^2 -12(y-8) = 0

Answer 2

solution:you must be solved for the y of way implicit

-2x^2+16x-224=-24y
2x^2-16x+224=24y
(1/12)x^2-(2/3)x+(224/24)=y

and solve it