What is the standard form of 4x²+4y²-20x+12y-2=0

Answer 1

4x²+4y²-20x+12y-2=0
4x²-20x+4y²+12y = 2
4(x²-5x) + 4(y²+3y) = 2
4(x²-5x+25/4) + 4(y²+3y+9/4) = 2 + 4*25/4 + 4*9/4
4(x-5/2)² + 4(y+3/2)² = 36
(x-5/2)² + (y+3/2)² = 9

Answer 2

why is it nine. It should be =6

Answer 3

Thanks for this solution it helps me lot heheehag

Answer 4

4x²+4y²+12y-7=0

Answer 5

4X²+4Y²+12Y-7=7