Ask a New Question
Search
What is the standard equation of a hyperbola given the vertices (7,-2) , (5,-2) and asymptotes " y= 11x - 68 " & " y= 11x + 64 "?
1 answer
center is at (6,-2)
a = 1
b/a = 11, so b=11
Ask a New Question
or
answer this question
.