To determine the standard deviation from the information given, let's clarify a few key points about the statistics provided:
- Mean: You mentioned a mean of 241.
- Variance: It seems you mentioned two values related to variance (4489 and 2067.79). However, variance should have a single consistent value for a data set. If 2067.79 is meant to be the variance, we will use that.
The standard deviation is the square root of the variance.
If we use the variance of 2067.79, the calculation for the standard deviation would be:
\[ \text{Standard Deviation} = \sqrt{\text{Variance}} = \sqrt{2067.79} \]
Calculating this gives:
\[ \text{Standard Deviation} \approx 45.5 \]
So, if we take the variance of 2067.79 as correct, the standard deviation of the data would be approximately 45.5. If you meant something else regarding the variances, please provide clarification!