Asked by Jamie
What is the spring constant of a spring that stores 25 J of elastic potential energy when compressed by 7.5 cm from its relaxed length?
I know that I should chnage 7.5 cm into .075 m. Is this equation correct? U(x)= 1/2kx^2. I should have gotten 89N/cm for the correct answer but it isn't working out.
U= 1/2 k x^2
k= 2U/x^2 = 2*25/.075^2=8900N/m^2 This does not convert to the answer you cited.
Or you can work it in cm..
U= 1/2 k x^2
2U/x^2 = 2*25/7.5^2 N/cm
I know that I should chnage 7.5 cm into .075 m. Is this equation correct? U(x)= 1/2kx^2. I should have gotten 89N/cm for the correct answer but it isn't working out.
U= 1/2 k x^2
k= 2U/x^2 = 2*25/.075^2=8900N/m^2 This does not convert to the answer you cited.
Or you can work it in cm..
U= 1/2 k x^2
2U/x^2 = 2*25/7.5^2 N/cm
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.