The specific heat capacity of water is 4.18 J/g°C. To find the specific heat capacity of 6.09 mols of water, we first need to convert the amount of water from moles to grams.
The molar mass of water (H2O) is approximately 18 g/mol. Therefore, 6.09 moles of water is equal to 6.09 moles * 18 g/mol = 109.62 grams.
Now, we can calculate the specific heat capacity of 6.09 mols of water:
Specific heat capacity = 4.18 J/g°C
Specific heat capacity = 4.18 J/g°C * 109.62 g = 457.64 J/°C
Therefore, the specific heat capacity of 6.09 mols of water is 457.64 J/°C.
What is the specific heat capacity of 6.09 mols of water liquor?
1 answer