To solve the system of equations:
- \(6c - 9d = 111\) (Equation 1)
- \(5c - 9d = 103\) (Equation 2)
We can eliminate \(d\) by subtracting Equation 2 from Equation 1.
Subtract Equation 2 from Equation 1:
\[ (6c - 9d) - (5c - 9d) = 111 - 103 \]
This simplifies to:
\[ 6c - 5c - 9d + 9d = 111 - 103 \]
\[ c = 8 \]
Now that we have \(c = 8\), we can substitute this value into either of the original equations to find \(d\). Using Equation 2:
\[ 5c - 9d = 103 \]
Substituting \(c = 8\):
\[ 5(8) - 9d = 103 \]
\[ 40 - 9d = 103 \]
Now isolate \(d\):
\[ -9d = 103 - 40 \]
\[ -9d = 63 \]
\[ d = \frac{63}{-9} = -7 \]
Thus, the solution to the system of equations in ordered pair form is:
\[ \boxed{(8, -7)} \]