4x + 3(x-2) = 8x - (6+x)
First, distribute 3 to (x-2):
4x + 3x - 6 = 8x - 6 - x
Combine like terms on both sides:
7x - 6 = 7x - 6
Subtract 7x from both sides:
7x - 7x - 6 = 7x - 7x - 6
-6 = -6
Since -6 = -6 is always true, this equation has infinite solutions.
What is the solution to the equation below? 4x+3(x−2)=8x−(6+x)
This problem requires you to show your work. (1 point)
Responses
x=−4
no solution
infinite solutions
x=6
1 answer