To solve the equation 3(2k + 3) = 6 - (3k - 5), let's first expand both sides of the equation:
On the left-hand side, we multiply 3 by each term inside the parentheses:
3 * 2k + 3 * 3 = 6k + 9
On the right-hand side, we distribute the negative sign inside the parentheses:
6 - (3k - 5) = 6 - 3k + 5
(Notice that - (3k - 5) becomes - 3k + 5 when we distribute the minus sign.)
Now, let's rewrite the equation with these expanded terms:
6k + 9 = 6 - 3k + 5
Next, combine like terms on the right-hand side of the equation:
6k + 9 = 11 - 3k
Now, we want to get all the k terms on one side of the equation and the constant terms on the other side. Let's add 3k to both sides of the equation:
6k + 3k + 9 = 11
Combine the k terms on the left:
9k + 9 = 11
Now, let's isolate the k term by subtracting 9 from both sides of the equation:
9k = 11 - 9
9k = 2
Finally, divide both sides of the equation by 9 to solve for k:
k = 2 / 9
The solution to the equation is k = 2 / 9.
What is the solution to 3(2k + 3) = 6 - (3k - 5)
1 answer