What is the solution set of 4^(x^(2)-4x)=2^(-6)

Answer 1

4^(x^2 - 4x) = 2^-6
(2^2)^(x^2-4x) = 2^-6
2^(2x^2 - 8x) = 2^-6

then
2x^2 - 8x = -6
x^2 - 4x + 3 = 0
(x-1)(x-3) = 0
x = 1 or x = 3

Answer 2

Thanks!