What is The solution set of 2k^2=21k-49 ?

Answer 1

this an be arranged to the quadratic
2k^2 - 21k + 49 = 0
(2k-7)(k-7) = 0
k = 7/2 or k-7

Answer 2

Thanks! how do u determine that they are both -7 though? Doesn't it have to equal 21? or doesn't that 21 matter?

Answer 3

why don't you expand (2k-7)(k-7 to see what you get?

Answer 4

oh it makes sense now thanks!

Answer 5

what is Expand:-4(2m - 7x + 9)