just use substitution. you know that
y = x+2, so now plug that into the other equation to get
x+2 = x^2+5x-3
x^2+4x-5 = 0
(x-1)(x+5) = 0
x = -5 or 1
So, y = -2 or 3
What is the solution of the linear-quadratic system of equations?
{y = x^2 + 5x - 3
{y - x = 2
So confused about how to do this any help is appreciated.
1 answer
1 answer