Asked by dw abt it
What is the solution of the following system?
Use the elimination method.
{4x+2y=66x−4y=−12
Responses
The solution is (32, 0) .
The solution is begin ordered pair 3 over 2comma 0 end ordered pair .
The solution is (0, 3) .
The solution is begin ordered pair 0 comma 3 end ordered pair .
There are an infinite number of solutions.
There are an infinite number of solutions.
There is no solution.
Use the elimination method.
{4x+2y=66x−4y=−12
Responses
The solution is (32, 0) .
The solution is begin ordered pair 3 over 2comma 0 end ordered pair .
The solution is (0, 3) .
The solution is begin ordered pair 0 comma 3 end ordered pair .
There are an infinite number of solutions.
There are an infinite number of solutions.
There is no solution.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the system of equations using the elimination method, we start with the given equations:
1. \( 4x + 2y = 6 \)
2. \( x - 4y = -12 \)
Let's simplify the first equation:
1. \( 4x + 2y = 6 \) can be divided by 2:
\[ 2x + y = 3 \] (Equation 1)
Now we rewrite the second equation:
2. \( x - 4y = -12 \) can be left as is:
\[ x - 4y = -12 \] (Equation 2)
Next, we can express \( y \) in terms of \( x \) using Equation 1:
\[ y = 3 - 2x \]
Now, let's substitute this expression for \( y \) back into Equation 2:
\[
x - 4(3 - 2x) = -12
\]
Expanding and simplifying:
\[
x - 12 + 8x = -12
\]
\[
9x - 12 = -12
\]
Adding 12 to both sides:
\[
9x = 0
\]
Now, solving for \( x \):
\[
x = 0
\]
Next, we substitute \( x = 0 \) back into the expression for \( y \):
\[
y = 3 - 2(0) = 3
\]
Thus, the solution to the system of equations is:
\[
(x, y) = (0, 3)
\]
So, the correct response is:
**The solution is (0, 3).**
1. \( 4x + 2y = 6 \)
2. \( x - 4y = -12 \)
Let's simplify the first equation:
1. \( 4x + 2y = 6 \) can be divided by 2:
\[ 2x + y = 3 \] (Equation 1)
Now we rewrite the second equation:
2. \( x - 4y = -12 \) can be left as is:
\[ x - 4y = -12 \] (Equation 2)
Next, we can express \( y \) in terms of \( x \) using Equation 1:
\[ y = 3 - 2x \]
Now, let's substitute this expression for \( y \) back into Equation 2:
\[
x - 4(3 - 2x) = -12
\]
Expanding and simplifying:
\[
x - 12 + 8x = -12
\]
\[
9x - 12 = -12
\]
Adding 12 to both sides:
\[
9x = 0
\]
Now, solving for \( x \):
\[
x = 0
\]
Next, we substitute \( x = 0 \) back into the expression for \( y \):
\[
y = 3 - 2(0) = 3
\]
Thus, the solution to the system of equations is:
\[
(x, y) = (0, 3)
\]
So, the correct response is:
**The solution is (0, 3).**
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