What is the solution of the equation

9/10 x + ⅘ = 28

X = 90/4

X = 133/5

X = 275/9

X = 97/3

1 answer

To solve the equation

\[ \frac{9}{10}x + \frac{4}{5} = 28, \]

we can start by isolating \( x \).

  1. Subtract \( \frac{4}{5} \) from both sides:

\[ \frac{9}{10}x = 28 - \frac{4}{5}. \]

  1. To perform the subtraction, we need a common denominator. The common denominator for \( 28 \) (which is \( \frac{28 \cdot 5}{5} = \frac{140}{5}\)) and \( \frac{4}{5} \) is \( 5 \):

\[ 28 = \frac{140}{5}, \quad \text{thus,} \] \[ 28 - \frac{4}{5} = \frac{140}{5} - \frac{4}{5} = \frac{136}{5}. \]

So now the equation looks like this:

\[ \frac{9}{10}x = \frac{136}{5}. \]

  1. To get rid of the fraction, multiply both sides by \( \frac{10}{9} \):

\[ x = \frac{136}{5} \cdot \frac{10}{9}. \]

  1. Simplifying this:

\[ x = \frac{1360}{45}. \]

  1. Now let's reduce \( \frac{1360}{45} \):
  • Factor both \( 1360 \) and \( 45 \):
    • \( 1360 = 2^4 \times 5 \times 17 \)
    • \( 45 = 3^2 \times 5 \)

The common factor is \( 5 \):

\[ x = \frac{1360 \div 5}{45 \div 5} = \frac{272}{9}. \]

Now we will compare this result with the options you provided:

  • \( \frac{90}{4} = 22.5 \)
  • \( \frac{133}{5} = 26.6 \)
  • \( \frac{275}{9} \) (approximately 30.56)
  • \( \frac{97}{3} \) (approximately 32.33)

Since \( \frac{272}{9} \approx 30.22 \) does not match any of your provided solutions either.

Let me check the calculation once more:

Returning to \( x = \frac{1360}{45} \):

\[ \frac{1360 \div 5}{45 \div 5} = \frac{272}{9}. \]

So the correct answer isn't available in the given options. The solution to the equation is \( x = \frac{272}{9} \).