What is the solution of 2 square root of 3x+4 (-9=13 is not part of the square root) -9=13

1 answer

Let's start by interpreting the equation provided. It seems like there might be a minor misunderstanding in the equation format. Based on what you've written, it looks like you're trying to solve for \( x \) in the following equation:

\[ 2 \sqrt{3x + 4} - 9 = 13 \]

To solve for \( x \), we will first isolate the square root term. Here are the steps:

  1. Add 9 to both sides:

\[ 2 \sqrt{3x + 4} = 22 \]

  1. Divide both sides by 2:

\[ \sqrt{3x + 4} = 11 \]

  1. Square both sides to eliminate the square root:

\[ 3x + 4 = 121 \]

  1. Subtract 4 from both sides:

\[ 3x = 117 \]

  1. Divide by 3:

\[ x = 39 \]

So, the solution to the equation is:

\[ \boxed{39} \]

Always remember to check if the obtained solution satisfies the original equation:

Plugging \( x = 39 \) back into the original equation:

\[ 2 \sqrt{3(39) + 4} - 9 = 13 \]

Calculating inside the square root:

\[ 3(39) + 4 = 117 + 4 = 121 \]

So we have:

\[ 2 \sqrt{121} - 9 = 13 \]

Since \( \sqrt{121} = 11 \):

\[ 2(11) - 9 = 13 \implies 22 - 9 = 13 \implies 13 = 13 \]

The solution checks out, confirming that \( x = 39 \) is indeed correct.