from the first equation:
x = -(6y+4)
substitute that for x in the second equation
-3(6y+4) -4y = 10
-18y -12 -4y = 10
-22 y = 22
y = -1
now go back and get x
x = -(6*-1 + 4)
x = - (-2)
x = 2
check
2 + 6*-1 = -4 sure enough
3*2 -4*-1 = 10 yes
What is the solution for the following system of linear equations?
x + 6y = -4 3x - 4y = 10
1 answer