.....................CaF2 ==> Ca^2+ + 2F^-
Write the Ksp expression for CaF2, the problem gives you the value for Ca^2+ and for F^-, cubstitute those values and solve for Kp. NOTE: The problem tells you that the (F^-) is 0.02M. Do NOT mutiply that by 2.
What is the solubility product of CaF2 if 0.1 M Ca2+ and 0.02 M F- are in solution just before precipitation occurs?
4.0 × 10^-5
The solubility product cannot be determined.
1.6 × 10^-4
2.0 × 10^-3
2 answers
It's 4.0 × 10^-5
1 answer