What is the solubility of a 0.20 M solution of Zn(CN)2? (Ksp = 8.0 × 10–12)?

Answer 1

.....Zn(CN)2 ==> Zn^2+ + 2CN^-
I.......solid..............0............0
C......solid..............x.............2x
E.......solid..............x............2x

Ksp = 8E-12(Zn^2+)(CN^-)^2

Plug the E line into the Ksp expression and solve for x = (Zn^2+) = solubility Zn(CN)2
Post your work if you get stuck.