What is the solubility equilibrium for Mn3(PO4)2?

Isn't it this..
Mn3(PO4)2 (s) --> 3Mn^+2 (aq) + 2PO4^-3
(aq)

but i keep getting it wrong. suggestions?

3 answers

Mn+3(PO4)+2 (s) to be exact**

You wrote the solubility equation correctly (except the arrow, you should have <-->). But I suspect they want the expression to find the solubility constant, which would be

Ks= [Mn++]³[PO₃²]

where [] means solubility in moles/liter.

https://chemistry.twu.edu/tutorial/KspSum.html

thank you!