What is the smallest prime divisor of 5^{19} + 7^{13} + 23?

Answer 1

The smallest prime divisor of an integer is the prime number that divides the integer without leaving a remainder.

To find the smallest prime divisor of the number 5^{19} + 7^{13} + 23, we can start by evaluating the expression:

5^{19} + 7^{13} + 23 ≈ 19073486328140

Now, we can try dividing this number by the smallest prime numbers (2, 3, 5, 7, 11, 13, 17, 19, 23) to find the smallest prime divisor.

By testing each of these prime numbers, we find that the smallest prime divisor of 5^{19} + 7^{13} + 23 is 3.