L=ℏ √l(l+1) =√l(l+1)• h/2π
l= n-1 =>
l=0, 1, 2, 3,4.
L(max) = √(4•5) • 6.63•10⁻³⁴/2π=4.72•10⁻³⁴ kg•m²/s
L(min)= 0
What is the smallest possible value for the angular momentum L of an electron in the n=5 shell?
Lmin= 0 kg*m^2/s
What is the largest possible value for the angular momentum L of an electron in the n=5 shell?
What is the Lmax? Please help I don't get this.Thank you!
1 answer