dy/dx = slope = 3 x^2 - 6 x + 5
where is that max or min ?
where its derivative is 0
d^2y/dx^2 = 0 = 6 x - 6
so x = 1
is that a max or a min?
take the ext derivative, if + it will be headed up and a min.
d^3y/dx^3 = 6
that is positive so the min slope is at x = 1
that slope is
3 x^2 - 6 x + 5 = 3-6+5 = 2
What is the smallest possible slope for a tangent to y=x^3 - 3x^2 + 5x?
(I'm unsure how to approach this problem, if you know how to solve it, please explain step by step. THANK YOU!!!)
3 answers
THANK YOU SO MUCH!!!
You are welcome.
1 answer