What is the slope of the tangent line to the graph at f(x)=x^2-5 at the point (2,-1)?

Answer 1

f(x)=x^sup2;-5
Use the power rule to find f'(x)
=>
f'(x)=2x
at point P(2,-1),
x=2
therefore
f'(x)=f'(2)=2*2=4
Slope of the tangent equals the derivative of the function at the point in question.