ok so far, though they already told you that f(2)=3 because the point (2,3) is on the graph.
As you know, the slope at any point (x,y) on the graph is 2x+2
So, the slope at x=2 is 6
Though, if this is pre-calc, how do you know the slope of the tangent to a curve? That's actual calculus.
What is the slope of the tangent line passing through the point (2, 3) of the graph of this function?
f(x)=x^2+2x−5
A) 1
B) 2
C) 3
D) 4
E) 6
f(2)=2^2+2(2)-5
f(2)=3
so is it c?
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