what is the slope of a line perpendicular to: y=5/8x-2

3 answers

To find the slope of a line that is perpendicular to the line given by the equation \( y = \frac{5}{8}x - 2 \), we first need to identify the slope of the original line.

In the equation \( y = \frac{5}{8}x - 2 \), the slope (\( m \)) is \( \frac{5}{8} \).

The slope of a line that is perpendicular to another line is the negative reciprocal of the original line's slope. To find the negative reciprocal of \( \frac{5}{8} \), we do the following:

  1. Flip the fraction: \( \frac{8}{5} \)
  2. Change the sign: \( -\frac{8}{5} \)

Therefore, the slope of a line perpendicular to the line \( y = \frac{5}{8}x - 2 \) is \( -\frac{8}{5} \).

so what's the answer

The slope of a line perpendicular to the line \( y = \frac{5}{8}x - 2 \) is \( -\frac{8}{5} \).