You are probably used to reading the slope from an equation in the form y = mx + b so let's change it to that
2x + 4y = 5
4y = -2x + 5
y = (-2/4)x + 5/4
so the slope of the given line is -1/2
recall that slopes of perpendicular lines are "opposite reciprocals" of each other
so the new line has slope +2
What is the slope of a line perpendicular to 2x + 4y = 5?
How would I figure this out? Thank you so much! :)
3 answers
This is a different problem...
Find the distance between A (0,1) and B (4,5).
Is this like the slope?
Find the distance between A (0,1) and B (4,5).
Is this like the slope?
the calculations might look similar, but the concept is much different.
you should have seen the formula
distance = √[(change in x's)^2 + (change in y's)^2]
= √[(4-0)^2 + (5-1)^2]
= √[16+16]
= √32
notice the same calculation as deltax and deltay ?
you should have seen the formula
distance = √[(change in x's)^2 + (change in y's)^2]
= √[(4-0)^2 + (5-1)^2]
= √[16+16]
= √32
notice the same calculation as deltax and deltay ?
0 answers