To find the slope and the y-intercept of the equation \( 9 + 272x = -32y \), we first need to rearrange it into the slope-intercept form, which is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
Starting with the equation:
\[ 9 + 272x = -32y \]
We can isolate \( y \) by following these steps:
- Subtract \( 9 \) and then divide by \( -32 \):
\[ -32y = 272x + 9 \]
- Divide everything by \( -32 \):
\[ y = -\frac{272}{32}x - \frac{9}{32} \]
- Simplify the coefficients:
The slope \( m \):
\[ -\frac{272}{32} = -\frac{17}{2} \]
The y-intercept \( b \):
\[ -\frac{9}{32} \]
Thus, the y-intercept as an ordered pair is \( (0, -\frac{9}{32}) \).
Now, summarizing our findings:
- The slope is \( -\frac{17}{2} \).
- The y-intercept is \( (0, -\frac{9}{32}) \).
So the answers are:
The slope is \( -\frac{17}{2} \). The y-intercept is \( (0, -\frac{9}{32}) \).
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