To find the slope and the y-intercept of the equation \( 9 + 272x = -32y \), we need to rearrange it into the slope-intercept form (\( y = mx + b \)), where \( m \) is the slope and \( b \) is the y-intercept.
Starting with the equation:
\[ 9 + 272x = -32y \]
First, we isolate \( y \) by moving the term involving \( 9 \) and \( 272x \) to the other side:
\[ -32y = -272x - 9 \]
Next, divide all terms by \(-32\):
\[ y = \frac{272}{32}x + \frac{9}{32} \]
Now simplify \(\frac{272}{32}\):
\[ y = 8.5x + \frac{9}{32} \]
So now we see that the slope \( m \) is \( 8.5 \), and the y-intercept \( b \) is \(\frac{9}{32}\).
The y-intercept as an ordered pair is \( (0, \frac{9}{32}) \).
Therefore:
- The slope is \( 8.5 \).
- The y-intercept is \( (0, \frac{9}{32}) \).