What is the shortest possible length of a triangle side facing an angle of 20 degrees, if one of the other sides is 5? (answer should be a decimal number, correct within 0.001)

Answer 1

The shortest possible length of triangle ABC, where ∠B = 20°, and BC=5 can be obtained by making AC perpendicular to AB.
This way, ∠A is 90° and the side AC can be obtained by the trigonometric formula:
AC = BC*sin(20°).