What is the set of quantum numbers for the last three electrons in an iodine atom?
4 answers
ml = -4, -3, -2, -1, 0 1, 2, 3, 4. These arbitrarily correspond to the 5s, 5px, 5py, 5pz, 4dx2-y2, 4dz2, 4dxy, 4dxz, and 4dyz orbitals.
The three quantum numbers (n, l, and m) that describe an orbital are integers: 0, 1, 2, 3, and so on. The principal quantum number (n) cannot be zero. The allowed values of n are therefore 1, 2, 3, 4, and so on. The angular quantum number (l) can be any integer between 0 and n - 1.
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Note to above answers:
Since the last 5 electrons in I are 5p5, the 5px, 5py and 5pz are the only three
orbitals involved; i.e., there are no electrons in those d orbitals shown.
Since the last 5 electrons in I are 5p5, the 5px, 5py and 5pz are the only three
orbitals involved; i.e., there are no electrons in those d orbitals shown.