What is the rotational kinetic energy of a planet about its spin axis? Model the planet as a uniform sphere of radius 6000 km, and mass 6.21 x 10^24 kg. Assume it has a rotational period of 24.0 h.

Answer 1

I=2mR²/5
ω=2π/T
KE= Iω²/2

Answer 2

KE= m(R^2)ω²/5