To calculate the resistance of the wire, we can use the principle of a meter bridge.
According to the principle of a meter bridge,
Resistance of the wire = (Length of wire opposing standard resistor/Length of standard resistor) x Standard resistance
Given that the length of the wire opposing the standard resistor is 56 cm and the length of the standard resistor is 44 cm (since a meter bridge is one meter long), and the standard resistance is 5 ohms, we can plug in the values to the formula:
Resistance of the wire = (56 cm / 44 cm) x 5 ohms
Resistance of the wire = (1.27) x 5 ohms
Resistance of the wire = 6.35 ohms
Therefore, the resistance of the wire is 6.35 ohms.
What is the resistance of a wire if it balances a standard resistor of 5 ohms at the 56 cm from the end of the meter-bridge?
Help me please!
1 answer