Asked by jodie
What is the relationship between the degree of a polynomial and the number of zeros (roots) it posses? Be sure to explain in your answer how prime polynomials violate this relationship.
Answers
Answered by
bobpursley
an equation to degree n, has n roots. This is always true, never violated. Never.
Now, if the range of the variables are over the Real Number set only, then some of the roots cannot be written because they exclude the actual roots, complex numbers.
Example(X^2+1)=0
x^2=-1
x= +- sqrt (-1) which is not a real number. If you allow sqrt(-1)=i, then the two roots are +-i.
The idea of "prime" polynomials seems to have some following amongst those whose minds do not comprehend the wonder of complex and imaginary numbers.
Now, if the range of the variables are over the Real Number set only, then some of the roots cannot be written because they exclude the actual roots, complex numbers.
Example(X^2+1)=0
x^2=-1
x= +- sqrt (-1) which is not a real number. If you allow sqrt(-1)=i, then the two roots are +-i.
The idea of "prime" polynomials seems to have some following amongst those whose minds do not comprehend the wonder of complex and imaginary numbers.
Answered by
Emishi gupta
abcdefghijklmnopqrstuvwxyz
sorry
sorry
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