What is the reaction that would occur in a galvanic cell between solutions of Al3+ and Pb2, where would oxidation and reduction take place, and what would the cell potentials be?

Answer 1

Aluminum is much more prone to oxidation, so it will lose electrons (oxidation).
Half cell potentials would be
Al>>Al^3+3e -1.66 is reduction potential
Pb>>Pb^2 + 2e -.13 is reduction potential
If Eo means oxidation potential (-reduction potential)
Cell potential = EoCell= Eo_Red,Cathode−Eo_Red,Anode
then
Cell potential= 1.66-(-1.3)=1.79 volts.

check my thinking.

Answer 2

bobpursley, I think the calculation is wrong.
Al is oxidation, Pb is reduction. Ecell= E reduction (Pb) - E oxidation

So the cell potential will be Ecell = -0.13 - (+1.68) = -1.81 V