5KI + 6HCl + KIO3 ==> 3I2 + 3H2O + 6KCl
I2 + 2Na2S2O3 ==> 2NaI + Na2S4O6
Here are the equations for the liberation of I2 and titration of same with thiosulfate. If you can't work the problem(s) from here, post with the numbers and a clear explanation of what you don't understand.
What is the reaction & calculation when KIO3 mixed with KI, HCl by titration with Na2S2O3?
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