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what is the rate law of S2O8^2- + 3I- ---> 2SO4^2- + I3-

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I did 3 Experiments and got 3 rate as the following:Exp1: (S2O8)2-:0.05M; I-:0.05M rate:1.7x10^-5 M/s Exp2: (S2O8)2-:0.10M;
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what is the rate law of S2O8^2- + 3I---> 2SO4^2- + I3-
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For a reaction involving ionic reactants described by the mechanism given byA + B <===> (A-B)* ===> P log k= log k1Kc + 1.0332
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Calculate the concentrations of S2O8 2-, I-, S2O32 2- in moles per litre of reaction mixture given the following:20mL of 0.1 M
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