The rate constant of a first order reaction can be determined using the equation:
t1/2 = ln(2) / k
where t1/2 is the half-life of the reaction and k is the rate constant.
Rearranging the equation, we get:
k = ln(2) / t1/2
Substituting t1/2 = 30.0 seconds, we get:
k = ln(2) / 30.0 seconds
Using a calculator, we get:
k = 0.0231 s^-1
Therefore, the rate constant of the first order reaction is 0.0231 s^-1 at a certain temperature.
What is the rate constant of first order reaction with a ualf life of 30.0 seconds at a certsin temperature
1 answer