The period is
T=2•π• sqrt (R³ /G•M)
Solve for R
What is the radius of a communications satellite’s orbital path that is in a uniform circular orbit around Earth and has a period of exactly 24.0 hours (86,400 seconds). (Measurement is from the center of Earth.)
G = 6.67 × 10-11 N.m2/kg2
ME = 5.98 × 1024 kg
1 hr = 3,600 s
2 answers
What is the radius of a communications satellite’s orbital path that is in a uniform circular orbit around Earth and has a period of exactly 24.0 hours (86,400 seconds). (Measurement is from the center of Earth.)