The radius of the electron orbit of a hydrogen atom for a given value of n is given by the formula:
r = (52.9 pm) x n^2
where n is the principal quantum number and pm stands for picometers.
For n = 4, we have:
r = (52.9 pm) x 4^2
r = 52.9 pm x 16
r = 846.4 pm
Therefore, the radius of the electron orbit of a hydrogen atom for n = 4 is 846.4 picometers, which is equivalent to 0.8464 nanometers.
What is the radius in nm of the electron orbit of a hydrogen atom for n = 4?
1 answer