what is the quotient of -96x^2/12x^2

Answer 1

To find the quotient of \(-96x^2\) divided by \(12x^2\), you can divide the coefficients and cancel the variable terms:

\[ \frac{-96x^2}{12x^2} = \frac{-96}{12} \cdot \frac{x^2}{x^2} \]

Calculating the coefficients:

\[ \frac{-96}{12} = -8 \]

And since \(\frac{x^2}{x^2} = 1\), the quotient simplifies to:

\[ -8 \cdot 1 = -8 \]

Thus, the final result is:

\[ \boxed{-8} \]