What is the quotient of -96x^2/12x^2

Answer 1

To find the quotient of \(-96x^2\) divided by \(12x^2\), you can divide the coefficients and use the properties of exponents.

1. Divide the coefficients: \(-96 / 12 = -8\)

2. Divide the \(x^2\) terms: \(x^2 / x^2 = 1\)

Putting it all together, we get:

\[ \frac{-96x^2}{12x^2} = -8 \cdot 1 = -8 \]

Therefore, the quotient is \(-8\).