What is the quotient of −5/9÷1/5?Write the answer as a mixed number.(1 point)

9 answers

To find the quotient of \(-\frac{5}{9} \div \frac{1}{5}\), you can multiply by the reciprocal of the second fraction:

\[ -\frac{5}{9} \times \frac{5}{1} = -\frac{5 \times 5}{9 \times 1} = -\frac{25}{9} \]

Now, to write \(-\frac{25}{9}\) as a mixed number, you need to divide 25 by 9.

25 divided by 9 is 2 with a remainder of 7. This means:

\[ -\frac{25}{9} = -2 \frac{7}{9} \]

So, the final answer as a mixed number is:

\[ -2 \frac{7}{9} \]

as a mixed number

The quotient of \(-\frac{5}{9} \div \frac{1}{5}\) was calculated as \(-\frac{25}{9}\). To express \(-\frac{25}{9}\) as a mixed number:

  1. Divide 25 by 9.
    • 9 goes into 25 two times (since \(9 \times 2 = 18\)).
    • The remainder is \(25 - 18 = 7\).

Therefore, \(-\frac{25}{9}\) can be expressed as: \[ -2\frac{7}{9} \]

So, the answer as a mixed number is indeed: \[ -2\frac{7}{9} \]

its not right

I apologize for any confusion. Let's work through the calculations step by step again to ensure we get the correct answer.

We want to calculate \(-\frac{5}{9} \div \frac{1}{5}\).

Dividing by a fraction is equivalent to multiplying by its reciprocal:

\[ -\frac{5}{9} \div \frac{1}{5} = -\frac{5}{9} \times \frac{5}{1} \]

Now, perform the multiplication:

\[ -\frac{5 \times 5}{9 \times 1} = -\frac{25}{9} \]

Now, to convert \(-\frac{25}{9}\) into a mixed number:

  1. Divide 25 by 9. The result is 2, because \(9 \times 2 = 18\).
  2. The remainder is \(25 - 18 = 7\).

Thus, we can express \(-\frac{25}{9}\) as:

\[ -2 \frac{7}{9} \]

This is technically correct, but if you're looking for a positive mixed number representation, you could say \(2 \frac{7}{9}\) with a negative sign in front.

The answer, as a mixed number, is

\[ -2 \frac{7}{9} \]

If you believe there's an error or are looking for a different format, please let me know!

don't give an explanation just the answer

The answer is \(-2 \frac{7}{9}\).

You're welcome! If you have any more questions, feel free to ask!