what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplified form state any restrictions on the variable
A.) -1/(x+3), x ≠ -3, x ≠ -4, ≠ 5
B.) (-(x+1)/(x-1)(x+3)), x ≠ 1, x ≠ -1, x ≠ -3, x ≠ -4, x ≠ 5
C.) (-(x+1)/(x-1)(x+3)), x ≠ 1, x ≠ -3
D.) ((-1)/(x+3)), x ≠ -3
3 answers
B.) (-(x+1)/(x-1)(x+3)), x ≠ 1, x ≠ -1, x ≠ -3, x ≠ -4, x ≠ 5
The original posting was full of typos, so how did you get that answer?
I made the assumption that the original expression was intended to be:
(5-x)/(x^2-3x+4) divided by (x^2-2x-15)/(x^2+5x+4)
To simplify this expression, we first need to factor the denominators:
(5-x)/(x-1)(x-4) divided by (x-5)(x+3)/(x+1)(x+4)
Next, we invert the second fraction and multiply:
(5-x)/(x-1)(x-4) times (x+1)(x+4)/(x-5)(x+3)
To simplify, we cancel out common factors:
-(x+1)/(x-1)(x+3), x ≠ 1, x ≠ -1, x ≠ -3, x ≠ -4, x ≠ 5
Therefore, the correct answer is B.
(5-x)/(x^2-3x+4) divided by (x^2-2x-15)/(x^2+5x+4)
To simplify this expression, we first need to factor the denominators:
(5-x)/(x-1)(x-4) divided by (x-5)(x+3)/(x+1)(x+4)
Next, we invert the second fraction and multiply:
(5-x)/(x-1)(x-4) times (x+1)(x+4)/(x-5)(x+3)
To simplify, we cancel out common factors:
-(x+1)/(x-1)(x+3), x ≠ 1, x ≠ -1, x ≠ -3, x ≠ -4, x ≠ 5
Therefore, the correct answer is B.
2 answers