To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we can use the distributive property (also known as the FOIL method in the case of binomials).
Let's distribute each term from the first polynomial to each term in the second polynomial:
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Multiply \(x^2y\) by \(x^2\): \[ x^2y \cdot x^2 = x^4y \]
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Multiply \(x^2y\) by \(-y\): \[ x^2y \cdot (-y) = -x^2y^2 \]
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Multiply \(2\) by \(x^2\): \[ 2 \cdot x^2 = 2x^2 \]
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Multiply \(2\) by \(-y\): \[ 2 \cdot (-y) = -2y \]
Now, we can combine all of these results to get the final form of the product:
\[ x^4y - x^2y^2 + 2x^2 - 2y \]
Thus, the product of the polynomials \((x^2y + 2)(x^2 - y)\) is:
\[ \boxed{x^4y - x^2y^2 + 2x^2 - 2y} \]
From the given responses, the correct option is:
x4y−x2y2+2x2−2y (which matches with the last option listed).