To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we can use the distributive property (also known as the FOIL method for binomials).
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Distribute \(x^2y\) across \(x^2 - y\): \[ x^2y \cdot x^2 + x^2y \cdot (-y) = x^4y - x^2y^2 \]
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Distribute \(2\) across \(x^2 - y\): \[ 2 \cdot x^2 + 2 \cdot (-y) = 2x^2 - 2y \]
Now, combine all the terms from both distributions: \[ x^4y - x^2y^2 + 2x^2 - 2y \]
So, the final result is: \[ x^4y - x^2y^2 + 2x^2 - 2y \]
Looking through the provided responses, the one that matches this result is: \[ \text{x}^4\text{y} - \text{x}^2\text{y}^2 + 2\text{x}^2 - 2\text{y} \]
Thus, the correct answer is: \[ \text{x}^4\text{y} - \text{x}^2\text{y}^2 + 2\text{x}^2 - 2\text{y} \]