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What is the product of the polynomials (x^2y+2) * (x^2-y)? x^4y-x^2y^2+2x^2-2y x^4y-xy+x^2y x^4y+x^2-2y x^3y-x^2y^2+2x^2-2yAsked by .+* Lolbit *+.
What is the product of the polynomials (x^2y + 2) (x^2 - y)?
x^4y - x^2y^2 + 2x^2 - 2y
x^4y - xy + x^2y
x^4y = x^2 - 2y
x^3y - x^2y^2 + 2x^2 - 2y
x^4y - x^2y^2 + 2x^2 - 2y
x^4y - xy + x^2y
x^4y = x^2 - 2y
x^3y - x^2y^2 + 2x^2 - 2y
Answers
Answered by
GPT-4o mini
To find the product of the polynomials \((x^2y + 2)(x^2 - y)\), we can use the distributive property (also known as the FOIL method for binomials). We will multiply each term in the first polynomial by each term in the second polynomial:
1. Multiply \(x^2y\) by \(x^2\):
\[
x^2y \cdot x^2 = x^4y
\]
2. Multiply \(x^2y\) by \(-y\):
\[
x^2y \cdot (-y) = -x^2y^2
\]
3. Multiply \(2\) by \(x^2\):
\[
2 \cdot x^2 = 2x^2
\]
4. Multiply \(2\) by \(-y\):
\[
2 \cdot (-y) = -2y
\]
Now we combine all these results together:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Thus, the product of the polynomials \((x^2y + 2)(x^2 - y)\) is:
\[
\boxed{x^4y - x^2y^2 + 2x^2 - 2y}
\]
1. Multiply \(x^2y\) by \(x^2\):
\[
x^2y \cdot x^2 = x^4y
\]
2. Multiply \(x^2y\) by \(-y\):
\[
x^2y \cdot (-y) = -x^2y^2
\]
3. Multiply \(2\) by \(x^2\):
\[
2 \cdot x^2 = 2x^2
\]
4. Multiply \(2\) by \(-y\):
\[
2 \cdot (-y) = -2y
\]
Now we combine all these results together:
\[
x^4y - x^2y^2 + 2x^2 - 2y
\]
Thus, the product of the polynomials \((x^2y + 2)(x^2 - y)\) is:
\[
\boxed{x^4y - x^2y^2 + 2x^2 - 2y}
\]
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