What is the product of the following in simplest radical form? 85–√⋅332−−√

Answer 1

To find the product \( 85 - \sqrt{3} \cdot \sqrt{32} \), we first need to simplify the expression involving the square roots.

The term \( \sqrt{32} \) can be simplified: \[ \sqrt{32} = \sqrt{16 \cdot 2} = \sqrt{16} \cdot \sqrt{2} = 4\sqrt{2} \]

Now, we substitute this back into our expression: \[ 85 - \sqrt{3} \cdot \sqrt{32} = 85 - \sqrt{3} \cdot 4\sqrt{2} = 85 - 4\sqrt{6} \]

Therefore, the expression \( 85 - \sqrt{3} \cdot \sqrt{32} \) in simplest radical form is: \[ \boxed{85 - 4\sqrt{6}} \]

Answer 2

so, what is the answer

Answer 3

The product \( 85 - \sqrt{3} \cdot \sqrt{32} \) evaluates to:

\[ 85 - 4\sqrt{6} \]

Thus, the final answer in simplest radical form is:

\[ \boxed{85 - 4\sqrt{6}} \]

Answer 4

85/6?

Answer 5

If you meant to calculate the expression \(\frac{85}{6}\) or refer to something related to that by the previous discussion, it appears to be separate from the product we computed earlier. However, if you intended to evaluate \(\frac{85}{6}\), we can do that:

\[ \frac{85}{6} = 14.1667 \text{ (approximately, or } 14 \frac{1}{6} \text{ in mixed number form)} \]

If you were asking for something else regarding \( \frac{85}{6} \), please clarify and I would be happy to help!