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Original Question
What is the product of the following expression in simplest radical form? √81 ⋅ √16Question
What is the product of the following expression in simplest radical form?
√50 x √45
√50 x √45
Answers
Answer
thats not correct
Answered by
GPT-4o mini
To simplify the expression \( \sqrt{50} \times \sqrt{45} \), we start by using the property of square roots that states \( \sqrt{a} \times \sqrt{b} = \sqrt{a \times b} \). Therefore, we can combine the square roots:
\[
\sqrt{50} \times \sqrt{45} = \sqrt{50 \times 45}
\]
Next, we calculate \( 50 \times 45 \):
\[
50 \times 45 = 2250
\]
Now we have:
\[
\sqrt{50 \times 45} = \sqrt{2250}
\]
To simplify \( \sqrt{2250} \), we factor \( 2250 \) into its prime factors. First, we divide \( 2250 \) by \( 10 \):
\[
2250 = 225 \times 10
\]
Next, we focus on simplifying \( 225 \):
\[
225 = 15 \times 15 = 15^2
\]
Now we return to \( 10 \):
\[
10 = 2 \times 5
\]
Thus, we can write the factorization of \( 2250 \):
\[
2250 = 15^2 \times 2 \times 5 = 3^2 \times 5^2 \times 2
\]
This can be combined as follows:
\[
2250 = 2 \times 3^2 \times 5^2
\]
Now we apply the square root:
\[
\sqrt{2250} = \sqrt{2 \times 3^2 \times 5^2} = \sqrt{2} \times \sqrt{3^2} \times \sqrt{5^2}
\]
Knowing that \( \sqrt{3^2} = 3 \) and \( \sqrt{5^2} = 5 \), we have:
\[
\sqrt{2250} = \sqrt{2} \times 3 \times 5 = 15 \sqrt{2}
\]
Thus, the product of the original expression \( \sqrt{50} \times \sqrt{45} \) in simplest radical form is:
\[
\boxed{15\sqrt{2}}
\]
\[
\sqrt{50} \times \sqrt{45} = \sqrt{50 \times 45}
\]
Next, we calculate \( 50 \times 45 \):
\[
50 \times 45 = 2250
\]
Now we have:
\[
\sqrt{50 \times 45} = \sqrt{2250}
\]
To simplify \( \sqrt{2250} \), we factor \( 2250 \) into its prime factors. First, we divide \( 2250 \) by \( 10 \):
\[
2250 = 225 \times 10
\]
Next, we focus on simplifying \( 225 \):
\[
225 = 15 \times 15 = 15^2
\]
Now we return to \( 10 \):
\[
10 = 2 \times 5
\]
Thus, we can write the factorization of \( 2250 \):
\[
2250 = 15^2 \times 2 \times 5 = 3^2 \times 5^2 \times 2
\]
This can be combined as follows:
\[
2250 = 2 \times 3^2 \times 5^2
\]
Now we apply the square root:
\[
\sqrt{2250} = \sqrt{2 \times 3^2 \times 5^2} = \sqrt{2} \times \sqrt{3^2} \times \sqrt{5^2}
\]
Knowing that \( \sqrt{3^2} = 3 \) and \( \sqrt{5^2} = 5 \), we have:
\[
\sqrt{2250} = \sqrt{2} \times 3 \times 5 = 15 \sqrt{2}
\]
Thus, the product of the original expression \( \sqrt{50} \times \sqrt{45} \) in simplest radical form is:
\[
\boxed{15\sqrt{2}}
\]
Answered by
GPT-4o mini
Let's re-evaluate the expression \( \sqrt{50} \times \sqrt{45} \) step by step to ensure accuracy in our simplification.
### Step 1: Combine the Square Roots
Using the property of square roots that allows us to combine them:
\[
\sqrt{50} \times \sqrt{45} = \sqrt{50 \times 45}
\]
### Step 2: Calculate \( 50 \times 45 \)
Calculating the product:
\[
50 \times 45 = 2250
\]
### Step 3: Simplify \( \sqrt{2250} \)
Next, we need to simplify \( \sqrt{2250} \). Let's factor \( 2250 \).
Finding the prime factorization of \( 2250 \):
1. Start by dividing by \( 10 \):
\[
2250 = 225 \times 10
\]
\[
10 = 2 \times 5
\]
2. Now factor \( 225 \):
\[
225 = 15 \times 15 = 15^2
\]
\[
15 = 3 \times 5 \quad \text{so,} \quad 225 = (3 \times 5)^2 = 3^2 \times 5^2
\]
Thus,
\[
2250 = 2 \times 3^2 \times 5^2
\]
### Step 4: Taking the Square Root
Using the square root property:
\[
\sqrt{2250} = \sqrt{2 \times 3^2 \times 5^2} = \sqrt{2} \times \sqrt{3^2} \times \sqrt{5^2}
\]
Calculating the roots:
\[
\sqrt{3^2} = 3 \quad \text{and} \quad \sqrt{5^2} = 5
\]
Therefore:
\[
\sqrt{2250} = \sqrt{2} \times 3 \times 5 = 15 \sqrt{2}
\]
### Conclusion
The product \( \sqrt{50} \times \sqrt{45} = \sqrt{2250} = 15\sqrt{2} \) was simplified correctly.
Thus, the correct answer is:
\[
\boxed{15\sqrt{2}}
\]
If you believe there is still an error, please clarify or provide additional details.
### Step 1: Combine the Square Roots
Using the property of square roots that allows us to combine them:
\[
\sqrt{50} \times \sqrt{45} = \sqrt{50 \times 45}
\]
### Step 2: Calculate \( 50 \times 45 \)
Calculating the product:
\[
50 \times 45 = 2250
\]
### Step 3: Simplify \( \sqrt{2250} \)
Next, we need to simplify \( \sqrt{2250} \). Let's factor \( 2250 \).
Finding the prime factorization of \( 2250 \):
1. Start by dividing by \( 10 \):
\[
2250 = 225 \times 10
\]
\[
10 = 2 \times 5
\]
2. Now factor \( 225 \):
\[
225 = 15 \times 15 = 15^2
\]
\[
15 = 3 \times 5 \quad \text{so,} \quad 225 = (3 \times 5)^2 = 3^2 \times 5^2
\]
Thus,
\[
2250 = 2 \times 3^2 \times 5^2
\]
### Step 4: Taking the Square Root
Using the square root property:
\[
\sqrt{2250} = \sqrt{2 \times 3^2 \times 5^2} = \sqrt{2} \times \sqrt{3^2} \times \sqrt{5^2}
\]
Calculating the roots:
\[
\sqrt{3^2} = 3 \quad \text{and} \quad \sqrt{5^2} = 5
\]
Therefore:
\[
\sqrt{2250} = \sqrt{2} \times 3 \times 5 = 15 \sqrt{2}
\]
### Conclusion
The product \( \sqrt{50} \times \sqrt{45} = \sqrt{2250} = 15\sqrt{2} \) was simplified correctly.
Thus, the correct answer is:
\[
\boxed{15\sqrt{2}}
\]
If you believe there is still an error, please clarify or provide additional details.
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